Tricky part is that commas may be present within the field (that's why the quotes)
Yoda's solution will not work for files that have more than 6 columns, or files that have commas in the last two fields. E.g. file
will become
Probably not what you want.
I would suggest the following approach:
1. protect the comma within quotes by substituting it with some character
2. get rid of the 4th field
3. substitute the protect character with comma to get back the original
Hi
Can anyone what I am doing wrong while using cut command.
for f in *.log
do
logfilename=$f
Log "Log file Name: $logfilename"
logfile1=`basename $logfilename .log`
flength=${#logfile1}
Log "file length $flength"
from_length=$(($flength - 15))
Log "from... (2 Replies)
Hi,
I need a help with cut/awk command. I need to get certain values from a string provided. For example: i have a config file with below mentioned details
oracle="user=name"/"pass/word"@databasename.
I have used a command var1=`grep -w oracle sample.cfg | cut -d"=" -f2 | cut -d"/" -f1`.
... (10 Replies)
Hi Friends,
I have a file1
i want to retrieve only the fields which have DEP,CITY,TRANS as headers in other file.
Output:
I want to give the input as DEP,CITY,TRANS column names to get the output.
i used cut command .. but if i have 300 fileds it is more difficult to... (4 Replies)
Hi,
I have to display the value 16 present in "lcpu=16" which is the output of a command
# vmstat
System configuration: lcpu=16 mem=4096MB
I used as
# hdtype=`vmstat | grep "lcpu" | awk -F "=" '{print $2}'`
# echo $hdtype
16 mem
But I need to display only 16..
Am doing... (3 Replies)
hay
i am trying to get JUST the PID from the ps command.
my command line is:
ps -ef | grep "mintty" | cut -d' ' -f2
but i get an empty line. i assume that the delimiter is not just one space character, but can't figure out what should i do in order to do that.
i know i can use awk or cut... (8 Replies)
Hi,
My aim is to get the md5 hash of a file and store it in a variable.
var1="md5sum file1"
$var1
The above outputs fine but also contains the filename, so somthing like this 243ASsf25 file1
i just need to get the first part and put it into a variable.
var1="md5sum file1"... (5 Replies)
I'm a complete beginner in UNIX (and not a computer science student either), just undergoing a tutoring course. Trying to replicate the instructions on my own I directed output of the ls listing command (lists all files of my home directory ) to My_dir.tsv file (see the screenshot) to make use of... (9 Replies)
Hi Everyone,
I have a very simple problem and i am stuck in that from last 8 days. I tried many attempts, googled my query but all in vain.
I have a text file named "test.txt"
In that suppose i have contents like:
Java:
1 Object oriented programming language
2 Concepts of Abstraction... (5 Replies)
Hi,
I would like use the output of my cut command as a variable in my following awk command. Here's what I've written.
cut -f1 info.txt | awk -v i=xargs -F'' '{if($6 == $i) print $20}' summary.txt
Where obviously the 'xargs' doesn't do what I want. How can I pass my cut result to my awk... (3 Replies)