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Top Forums Shell Programming and Scripting Need help on awk for printing the function name inside each function Post 303012060 by RudiC on Monday 29th of January 2018 06:34:07 AM
Old 01-29-2018
awk's construct /var/ looks for exactly that: the three char sequence "v", "a", and "r". That is not recognised as a variable and thus not replaced by its value.
Try $0 ~ var or the match function.


EDIT: Not exactly sure what you're after, but would this go into the right direction:
Code:
awk '
1
/\(\)/  {sub (/\(\)/, _)
         var = $0
         L = NR + 1
        }
NR == L {print "echo \"" var "\""
        }
' scriptname


Last edited by RudiC; 01-29-2018 at 07:49 AM..
 

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SUBSTR_REPLACE(3)							 1							 SUBSTR_REPLACE(3)

substr_replace - Replace text within a portion of a string

SYNOPSIS
mixed substr_replace (mixed $string, mixed $replacement, mixed $start, [mixed $length]) DESCRIPTION
substr_replace(3) replaces a copy of $string delimited by the $start and (optionally) $length parameters with the string given in $replace- ment. PARAMETERS
o $string - The input string. An array of strings can be provided, in which case the replacements will occur on each string in turn. In this case, the $replacement, $start and $length parameters may be provided either as scalar values to be applied to each input string in turn, or as arrays, in which case the corresponding array element will be used for each input string. o $replacement - The replacement string. o $start - If $start is positive, the replacing will begin at the $start'th offset into $string. If $start is negative, the replacing will begin at the $start'th character from the end of $string. o $length - If given and is positive, it represents the length of the portion of $string which is to be replaced. If it is negative, it rep- resents the number of characters from the end of $string at which to stop replacing. If it is not given, then it will default to strlen( $string ); i.e. end the replacing at the end of $string. Of course, if $length is zero then this function will have the effect of inserting $replacement into $string at the given $start offset. RETURN VALUES
The result string is returned. If $string is an array then array is returned. EXAMPLES
Example #1 Simple substr_replace(3) examples <?php $var = 'ABCDEFGH:/MNRPQR/'; echo "Original: $var<hr /> "; /* These two examples replace all of $var with 'bob'. */ echo substr_replace($var, 'bob', 0) . "<br /> "; echo substr_replace($var, 'bob', 0, strlen($var)) . "<br /> "; /* Insert 'bob' right at the beginning of $var. */ echo substr_replace($var, 'bob', 0, 0) . "<br /> "; /* These next two replace 'MNRPQR' in $var with 'bob'. */ echo substr_replace($var, 'bob', 10, -1) . "<br /> "; echo substr_replace($var, 'bob', -7, -1) . "<br /> "; /* Delete 'MNRPQR' from $var. */ echo substr_replace($var, '', 10, -1) . "<br /> "; ?> Example #2 Using substr_replace(3) to replace multiple strings at once <?php $input = array('A: XXX', 'B: XXX', 'C: XXX'); // A simple case: replace XXX in each string with YYY. echo implode('; ', substr_replace($input, 'YYY', 3, 3))." "; // A more complicated case where each replacement is different. $replace = array('AAA', 'BBB', 'CCC'); echo implode('; ', substr_replace($input, $replace, 3, 3))." "; // Replace a different number of characters each time. $length = array(1, 2, 3); echo implode('; ', substr_replace($input, $replace, 3, $length))." "; ?> The above example will output: A: YYY; B: YYY; C: YYY A: AAA; B: BBB; C: CCC A: AAAXX; B: BBBX; C: CCC NOTES
Note This function is binary-safe. SEE ALSO
str_replace(3), substr(3), String access and modification by character. PHP Documentation Group SUBSTR_REPLACE(3)
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