How to Dynamically Pass Parameter to plsql Function & Capture its Output Value in a Shell Variable?
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1. The problem statement, all variables and given/known data:
2. Relevant commands, code, scripts, algorithms:
When I am passing like this function it is not working.
when I am passing like above like i am hardcoding the paramter in function the plsql function is working .
Please let me know how to pass the parameter dynamically to plssql function as well at the same time capture the output value in a shell variable 3. The attempts at a solution (include all code and scripts):
4. Complete Name of School (University), City (State), Country, Name of Professor, and Course Number (Link to Course):
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Oracle India, Bangalore,India
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Please use CODE tags as required by forum rules!
Last edited by sujitdas2104; 08-08-2017 at 10:00 AM..
Reason: Added CODE tags.
Hi Gurus,
I have request which needs to pass position parameter to a function. I tried below simple code, it doesn't work.
#!/bin/bash
func_1(){
echo $1
}
func_1
$ ./set_file abc
$
do I need add some to get the position para first?
thanks in advance. (3 Replies)
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