Shell Programming and Scripting

Hi

Am taking a value in a variable and i have to use that in listing files using grep

like
ls -ltr | grep "$variablename" filename...
but the variable contains spaces in it and i am not able to get the correct value(i.e., wid spaces)
if the variable has "day 2"(wid 2 spaces) in it am able to use this, only when it is enclosed in double qoutes.otherwise the value is "Day 2"(wid one space)

Can anyone help me out.....

Do you mean that you want to be able to find day..2 and day.2 (dots=spaces)?
That means the variable will have to be a regular expression or you will have to have two separate values to grep for like this:

Code:

grep -e 'day 2' -e 'day  2' filename

i am taking out themonth and day from the date command like

d=`date +%b %e`

am getting the result as Sep 9
but i want the value as Sep 9
and i have to take the result into a variable and again use that variable in other command

please help me out....

I'm not understanding - the two Sep 9 in your post above are the same. How are the supposed to be different - exactly.

Get the date as:

Code:

d=`date +%b%e`

Hi

Sorry ..It was mistyped
The first one is Sep 9 (wid one space between Sep and 9)
The second one is Sep 9(wid two spaces)

I think you mean "with", not "wid".

Try this:

Code:

ls -ltr | grep "$(date +'%b *%e')"