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strrpos(3) [php man page]

STRRPOS(3)								 1								STRRPOS(3)

strrpos - Find the position of the last occurrence of a substring in a string

SYNOPSIS
int strrpos (string $haystack, string $needle, [int $offset]) DESCRIPTION
Find the numeric position of the last occurrence of $needle in the $haystack string. PARAMETERS
o $haystack - The string to search in. o $needle - If $needle is not a string, it is converted to an integer and applied as the ordinal value of a character. o $offset - If specified, search will start this number of characters counted from the beginning of the string. If the value is negative, search will instead start from that many characters from the end of the string, searching backwards. RETURN VALUES
Returns the position where the needle exists relative to the beginnning of the $haystack string (independent of search direction or off- set). Also note that string positions start at 0, and not 1. Returns FALSE if the needle was not found. Warning This function may return Boolean FALSE, but may also return a non-Boolean value which evaluates to FALSE. Please read the section on Booleans for more information. Use the === operator for testing the return value of this function. CHANGELOG
+--------+---------------------------------------------------+ |Version | | | | | | | Description | | | | +--------+---------------------------------------------------+ | 5.0.0 | | | | | | | The $needle may now be a string of more than one | | | character. | | | | +--------+---------------------------------------------------+ EXAMPLES
Example #1 Checking if a needle is in the haystack It is easy to mistake the return values for "character found at position 0" and "character not found". Here's how to detect the difference: <?php $pos = strrpos($mystring, "b"); if ($pos === false) { // note: three equal signs // not found... } ?> Example #2 Searching with offsets <?php $foo = "0123456789a123456789b123456789c"; var_dump(strrpos($foo, '7', -5)); // Starts looking backwards five positions // from the end. Result: int(17) var_dump(strrpos($foo, '7', 20)); // Starts searching 20 positions into the // string. Result: int(27) var_dump(strrpos($foo, '7', 28)); // Result: bool(false) ?> SEE ALSO
strpos(3), stripos(3), strripos(3), strrchr(3), substr(3). PHP Documentation Group STRRPOS(3)

Check Out this Related Man Page

SUBSTR_COUNT(3) 							 1							   SUBSTR_COUNT(3)

substr_count - Count the number of substring occurrences

SYNOPSIS
int substr_count (string $haystack, string $needle, [int $offset], [int $length]) DESCRIPTION
substr_count(3) returns the number of times the $needle substring occurs in the $haystack string. Please note that $needle is case sensi- tive. Note This function doesn't count overlapped substrings. See the example below! PARAMETERS
o $haystack - The string to search in o $needle - The substring to search for o $offset - The offset where to start counting o $length - The maximum length after the specified offset to search for the substring. It outputs a warning if the offset plus the length is greater than the $haystack length. RETURN VALUES
This function returns an integer. CHANGELOG
+--------+-----------------------------------------------+ |Version | | | | | | | Description | | | | +--------+-----------------------------------------------+ | 5.1.0 | | | | | | | Added the $offset and the $length parameters | | | | +--------+-----------------------------------------------+ EXAMPLES
Example #1 A substr_count(3) example <?php $text = 'This is a test'; echo strlen($text); // 14 echo substr_count($text, 'is'); // 2 // the string is reduced to 's is a test', so it prints 1 echo substr_count($text, 'is', 3); // the text is reduced to 's i', so it prints 0 echo substr_count($text, 'is', 3, 3); // generates a warning because 5+10 > 14 echo substr_count($text, 'is', 5, 10); // prints only 1, because it doesn't count overlapped substrings $text2 = 'gcdgcdgcd'; echo substr_count($text2, 'gcdgcd'); ?> SEE ALSO
count_chars(3), strpos(3), substr(3), strstr(3). PHP Documentation Group SUBSTR_COUNT(3)
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