ok, i tried something i did before and i seem to be getting somewhere here. just one problem. line 100.25: 1506-068 (W) Operation between types "int*" and "int" is not allowed.
how do i get my number to save inside my integer array? (temp3 is a var int temp3[4])
thanks!
primal
_____________________________
im stuck! this is probably something basic that i just forgot how to do but ive been trying to get this working for a few days now and i cant figure it out. heres the deal:
part of the program im writing prompts the user for a 4 digit number and stores it into int *refNumber[4]. ive passed it to my function call, int insert(char *name[],int *refNumber[], int) but getting the info to store is whats not working. ive tried a few ways, but nothing.
this is how i did it for the name.... (inside a while loop)
printf("Enter clients name:\n");
fflush(stdin);
scanf("%[^\n]",temp);
name[count]=(char *)malloc(strlen(temp)+1);
strcpy(name[count],temp); temp is a a var (char temp[30])
**reference number code here **
count++;
ive tried strlen, strcpy, sizeof, a few others that i cant recall right now. im completely lost.
would any one be able to help me?
thanks!
primal
The way you are handling the name looks reasonable. You have an array of pointers to char, you calloc just enough space to hold each name, and you return the pointer. But with the name you are dealing with data whose length you cannot predict.
But the length of a 4 digit integer is predictable. And you can store all 4 digits in one int. So you should have an array of ints. You should pass that array to your function. And your function should just store the int in the array.
Your line
int *refNumber[4];
worries me. That is an array with 4 elements. Each element is a pointer to int. You still have no place to store any ints.
Do you really have a need to split the digits up, one per element? If so I would use chars rather than ints.
If i and j are integers, you can copy one to the other with just
i=j;
you don't really want to do something like:
strcpy((char *) &i, (char *) &j, sizeof int);
that's crazy.
If you need more help with this, I would need to how you allocate the data which is passed to the function, and the actual call to the function. If you change the prototype, show the new prototype as well.
"But the length of a 4 digit integer is predictable. And you can store all 4 digits in one int. So you should have an array of ints. You should pass that array to your function. And your function should just store the int in the array"
how do i do that?
thanks!
primal
heres my code, well the bit that pertains to this
Code:
void main(){
char choice[6], *name[30], ch;
int num, count=0, *refNumber[4];
int insert(char *name[],int *refNumber[],int);
count=insert(name,refNumber,count);
}
int insert(char *name[],int *refNumber[],int count){
int i, temp3[4];
char temp[30],choice[5];
printf("\nDo you want to enter client data?\n");
fflush(stdin);
scanf("%[^\n]", choice);
for(i=0;choice[i]!='\0';i++){
choice [i] = toupper(choice[i]);
}
while((!(strcmp(choice,"YES")==0) && !(strcmp(choice,"NO") == 0))){
printf("\nInvalid option!\t \"yes\" or \"no\"\n");
fflush (stdin);
scanf("%[^\n]", choice);
for(i=0;choice[i]!='\0';i++){
choice [i] = toupper(choice[i]);
}
}
while(strcmp(choice, "YES") ==0){
fflush(stdin);
printf("\nEnter Client Name:\n");
fflush(stdin);
scanf("%[^\n]", temp);
name[count] = (char *) malloc (strlen(temp) + 1);
strcpy (name[count], temp);
printf("\nEnter 4 Digit Reference Number:\n");
scanf("%d",&temp3[count]);
while(temp3[count]<1000||temp3[count]>9999){
printf("\nInvalid Option!");
printf("\nEnter 4 Digit Reference Number:\n");
scanf("%d",&temp3[count]);
}
refNumber[count]=temp3[count];
count++;
printf("\nDo you want to enter data for another client?\n");
fflush(stdin);
scanf("%[^\n]", choice);
for(i=0;choice[i]!='\0';i++){
choice [i] = toupper(choice[i]);
}
while((!(strcmp(choice,"YES")==0) && !(strcmp(choice,"NO") == 0))){
printf("\nInvalid option!\t \"yes\" or \"no\"\n");
fflush (stdin);
scanf("%[^\n]", choice);
for(i=0;choice[i]!='\0';i++){
choice [i] = toupper(choice[i]);
}
}
}
return count;
}
You are not checking for overflowing your arrays. I put that in. It's the LISTMAX stuff and a slight mode to your scanf's. I didn't like the way you passed count into your function. So I did that a little differently. And I added a few statements to print out the arrays to be sure that it was working.
You will want to bump up LISTMAX, I made it low for easy testing...
Here is my modified code...
Code:
#include <stdio.h>
#define LISTMAX 3
void main(){
char *name[LISTMAX], ch;
int num, count, refNumber[LISTMAX];
int i;
int insert(char *name[],int refNumber[]);
count=insert(name,refNumber);
printf("count = %d \n", count);
for(i=0; i<count; i++) {
printf("%30s %d\n", name[i], refNumber[i]);
}
exit(0);
}
int insert(char *name[],int refNumber[]){
int count;
int i, temp3[4];
char temp[30],choice[5];
count=0;
printf("\nDo you want to enter client data?\n");
fflush(stdin);
scanf("%5[^\n]", choice);
for(i=0;choice[i]!='\0';i++){
choice [i] = toupper(choice[i]);
}
while((!(strcmp(choice,"YES")==0) && !(strcmp(choice,"NO") == 0))){
printf("\nInvalid option!\t \"yes\" or \"no\"\n");
fflush(stdin);
scanf("%5[^\n]", choice);
for(i=0;choice[i]!='\0';i++){
choice [i] = toupper(choice[i]);
}
}
while(strcmp(choice, "YES") ==0){
printf("\nEnter Client Name:\n");
fflush(stdin);
scanf("%30[^\n]", temp);
name[count] = (char *) malloc (strlen(temp) + 1);
strcpy (name[count], temp);
printf("\nEnter 4 Digit Reference Number:\n");
fflush(stdin);
scanf("%4d",&temp3[count]);
while(temp3[count]<1000||temp3[count]>9999){
printf("\nInvalid Option!");
printf("\nEnter 4 Digit Reference Number:\n");
fflush(stdin);
scanf("%d",&temp3[count]);
}
refNumber[count]=temp3[count];
count++;
if (count == LISTMAX) {
printf("tables are full\n");
return LISTMAX;
}
printf("\nDo you want to enter data for another client?\n");
fflush(stdin);
scanf("%[^\n]", choice);
for(i=0;choice[i]!='\0';i++){
choice [i] = toupper(choice[i]);
}
while((!(strcmp(choice,"YES")==0) && !(strcmp(choice,"NO") == 0))){
printf("\nInvalid option!\t \"yes\" or \"no\"\n");
fflush(stdin);
scanf("%[^\n]", choice);
for(i=0;choice[i]!='\0';i++){
choice [i] = toupper(choice[i]);
}
}
}
return count;
}
Hello and Good day, I am currently studying C and I just finished learning about variables mainly those of integer type.
I am wondering if the list below are all there is to integer variables and there are still more that i have to learn.
Here are the list:
Char
Short
int
long
long long... (3 Replies)
Hi fellows!!
i'm doing something which is not working out for me properly which i don't understand why
nowdate=`date +%s`
echo $nowdate
now the problem how to convert a date which is stored in a variable
mydate="22/Oct/2011"
mydate=`date -d '$mydate' +%s`
it gives error... (11 Replies)
hello,
i am writing a script that takes the UID from the PASSWD and then i want
to increse the Number by one. for the Next user.
i cannot get this to work that a variable is as interger
example:
set i = 0
set $i = $+1
it's in tcsh if it's mather (10 Replies)
if i declare both but don't input any variables what values will the int array and file pointer array have on default, and if i want to reset any of the elements of both arrays to default, should i just set it to 0 or NULL or what? (1 Reply)
Hi all,
is there an easy way to convert integer to string in bash?
I have numbers like 1, 2, ..., 112, ...
and I would like to get
001 002 003 004 ...
Thank you,
Sarah (4 Replies)
Hey I am trying to calculate a number but I found out the expr I knew works only with integers. Any help. I want to calculate (120/220) *100.
Thanks! (2 Replies)
PHP question...
I have an SQL query that's pulled back user IDs as a set of columns. Rather than IDs, I want to use their names.
So I have an array of columns $col with values 1,7,3,12 etc and I've got an array $person with values "Fred", "Bert", "Tom" etc
So what I want to do is display the... (3 Replies)
HI
I want to round off an integer to the next multiple of 10 in shell script.
(i.e.,) 91 should be rounded off to 100
and 90 should be rounded off to 90
It would be very helpful, if you can help me in this.
Thanks in advance (4 Replies)
03-09-2002
integer arrays