10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
I have a lot of files with keywords and unique names. I'm using a shell script to refer to a simple pattern file with comma separated values in order to match on certain keywords. The problem is that I don't understand how to handle the wildcard values when I want to skip over the unique names.
... (5 Replies)
Discussion started by: abercrom
5 Replies
2. Shell Programming and Scripting
Hello,
Can you please help here?
DAY=$1
MONTH_MONDAY_YEAR = 1 2 3 4
for i in ${MONTH_${DAY}_YEAR}
do
echo ${i}
done
./test.sh MONDAY
./test.sh: line 3: MONTH_MONDAY_YEAR: command not found
./test.sh: line 10: ${MONTH_${DAY}_YEAR}: bad substitution (6 Replies)
Discussion started by: vino_hymi
6 Replies
3. Shell Programming and Scripting
Experts,
I want to set value of variables like this in bash shell:
i=5 ; L=100
I want variable d5 (that is d(i) ) to be assign the value of $L ,
d$i=$L ; echo $d5
Not working
Thanks., (3 Replies)
Discussion started by: rveri
3 Replies
4. Shell Programming and Scripting
Hello,
so i'm making a script, using dynamic variables and trying to expand them. So far it hasn't worked out too well so it seems that I need some help from you, the elite.
Example:
#!/bin/sh
counter=0
until (($counter>5))
counter2=1
until (($counter2>6)); do
if ;... (5 Replies)
Discussion started by: TehOne
5 Replies
5. Shell Programming and Scripting
I'm trying to make a sed substitution where the substitution pattern is an environment variable to be expanded, but the variable contains a "slash".
sed -e 's/<HOME_DIRECTORY>/'$HOME'/'This gives me the following error:
sed: -e expression #1, char 21: unknown option to `s'Obviously this is... (2 Replies)
Discussion started by: Ilja
2 Replies
6. Shell Programming and Scripting
Hi,
I'm using a for loop reading from an input file that contains files, whose path includes a variable name.
But the for loop doesn't expand the variable and therefore can't find the file.
Here's an example:
File BACKUPFILES
/home/John/alpha
/home/Sue/beta... (8 Replies)
Discussion started by: Hesiod
8 Replies
7. UNIX for Dummies Questions & Answers
Probably a stupid question... how do I use a wildcard in a variable in zsh? If I do:
var=*
echo $var
in bash, it will print all files/directories in the current directory. If I do it in zsh, it will only output an asterisk without the wildcard functionality. Thanks in advance! (1 Reply)
Discussion started by: RainbowLAr
1 Replies
8. UNIX for Dummies Questions & Answers
I am new to unix and would appreciate if someone could help.
I have an environment variable SourceFilePath=/db1/Src/test set on the unix server.
I want to expand this SHELL variable in a file using any command sed, awk etc
File contents is as follows:
var=$SourceFilePath/file.txt
... (2 Replies)
Discussion started by: debbie15
2 Replies
9. Shell Programming and Scripting
Dear all,
i dont know how to split one variable value in 2 variable. please send me any example.
variable1= "abcde developer"
now i want to seperate the values and seperator is space. (6 Replies)
Discussion started by: intikhabalam
6 Replies
10. UNIX for Dummies Questions & Answers
With the if statement:
if
How can I make it so it accepts a wildcard after the ${CURR_DAY_MONTH} variable?
Putting
a -f /webtrends/SUN/mrw2/access.${CURR_DAY_DAY}${CURR_DAY_MONTH}*
won't work, right? I think I need some kind of special character so it knows the wildcard is... (3 Replies)
Discussion started by: LordJezo
3 Replies